What is #int x*e^(x^2) dx# ?
1 Answer
Mar 24, 2016
Explanation:
Since
#d/(dx) e^(x^2) = 2x*e^(x^2)#
So:
#int x*e^(x^2) dx = 1/2 e^(x^2) + C#
Since
#d/(dx) e^(x^2) = 2x*e^(x^2)#
So:
#int x*e^(x^2) dx = 1/2 e^(x^2) + C#