# How does the concentration of 0.090*mol*L^-1 HCl(aq) compare to 0.90*mol*L^-1 HCl(aq)?

Mar 27, 2016

Is an order of magnitude LESS concentrated.

#### Explanation:

We simply divide the second concentration by the first:

$\frac{0.90 \cdot m o l \cdot {L}^{-} 1}{0.09 \cdot m o l \cdot {L}^{-} 1}$ $=$ $10$.