# Question #e769e

Mar 30, 2016

#### Answer:

$\implies x = - 6 \text{ or } x = + 7$

#### Explanation:

This is another way of asking you solve a quadratic equation being set to equal zero

From the question we have:

$\text{ } x = {x}^{2} - 42$

Rearranging gives

$\text{ } {x}^{2} - x - 42 = 0$

$\text{ } \left(x + 6\right) \left(x - 7\right) = 0$

$\implies x = - 6 \text{ or } x = + 7$