Question #b1a93

1 Answer
Aug 11, 2016

#x =56#

Explanation:

#log(x+4)-log6=1#

First step. The terms must be all logs or all numbers.
Do something with the 1. We know #1 = log 10#
(As no bases are shown, we assume they are 10.)

#log(x+4)-log6=log 10#

Second step
Write two log terms as one log term. single number/fraction)

If log terms are being added, then the numbers are being multiplied.
If log terms are being subtracted, then the numbers are being divided

#log((x+4)/(6) ) = log10#

Drop the logs on each side If log A = log B, then A = B

#(x+4)/(6) = 10#

Solve the equation

#x+4 = 60#
#x =56#

Substitute the answer into the original equation to check .

#log56 - log6 =1#