Question #79b63

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Answer 1 · 2016-07-07T15:18:37

1st term=3
2nd term =12
3rd term =48

Let
$" the 1st term of GP "=a$
$" and common ratio "=r$

$" So 2nd term"= ar " and 3rd term"=ar^2$

By the 1st condition

$(ar^2)/a=16=>r=sqrt16=4$

By the 2nd condition

$ar^2-a=45=>a(4^2-1)=45=>a=3$

Hence

$"1st term "=3$

$"2nd term "=12$

$"3rd term "= 48$