# Question 2da35

Jan 29, 2017

$150$ deer were tagged

#### Explanation:

We are told that 20% of 60%# are males older than $4 \frac{1}{2}$
There are 18 of these males.

If the total number of deer is $x$, we can write an equation to show the process:

$\frac{20}{100} \times \frac{60}{100} \times x = 18$

Now solve for $x$ by isolating it.

$\frac{\cancel{20}}{\cancel{100}} \textcolor{red}{\times \frac{\cancel{100}}{\cancel{20}}} \times \frac{\cancel{60}}{\cancel{100}} \textcolor{b l u e}{\times \frac{\cancel{100}}{\cancel{60}}} \times x = 18 \textcolor{red}{\times \frac{100}{20}} \textcolor{b l u e}{\times \frac{100}{60}}$

$x = {\cancel{18}}^{6} \times {\cancel{100}}^{5} / \cancel{20} \times {\cancel{100}}^{5} / {\cancel{60}}^{\cancel{3}}$

$x = 6 \times 5 \times 5$

$x = 150$