Question #863ff
1 Answer
Apr 5, 2016
Explanation:
The problem provides you with the solution's percent concentration by mass, which essentially tells you how much solute you for every
In this case, a
That is to say that you can make this solution by dissolving
#m_"solution" = overbrace("12.0 g")^(color(red)("solute")) + overbrace("88.0 g")^(color(blue)("solvent")) = "100. g"#
Since the solution contains