# What is the molarity of a 6.50*g mass of sucrose that is dissolved in a 450*mL volume of solution?

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$\text{Molarity}$ $=$ $\frac{6.50 \cdot g}{342.30 \cdot g \cdot m o {l}^{-} 1}$ $\times$ $\frac{1}{0.450 \cdot L}$