Question #6a172

1 Answer
A08
Apr 12, 2016

#20000N#

Explanation:

Let the ball be moving in the #x# direction with a speed of #100ms^-1#.

After hitting the wall, ball rebounds with the same speed. It implies that velocity is reversed but magnitude remains same.
#:.# Change in momentum #Delta vecp=massxx(vecv_f-vecv_i)#
#Delta |vecp|=2xx(200)=400Ns#
Time for which force is applied #1/50s#
We know that change of momentum#="Force"xx "time"#
#=>Delta vecp=vecFxxtime#,
or #vecF=Delta vecpxx1/(time)#
#=400xx1/(1/50)#
#=20000N#

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