Question

Question #1930d

Answer 1

`0.5 mol HCl_g x (22.4 L)/ (1 mol) = 12.1 L HCl_g`

Explanation:

At STP we can use Avogadro's value of 22.4 L per mole of gas.

Therefor 0.5 moles of HCl gas at STP would fill a volume of 12.1 L

`0.5 mol HCl_g x (22.4 L)/ (1 mol) = 12.1 L HCl_g`