# Question #1930d

##### 1 Answer
Apr 11, 2016

$0.5 m o l H C {l}_{g} x \frac{22.4 L}{1 m o l} = 12.1 L H C {l}_{g}$

#### Explanation:

At STP we can use Avogadro's value of 22.4 L per mole of gas.

Therefor 0.5 moles of HCl gas at STP would fill a volume of 12.1 L

$0.5 m o l H C {l}_{g} x \frac{22.4 L}{1 m o l} = 12.1 L H C {l}_{g}$