# Question #45686

##### 1 Answer

Here's my take on this.

#### Explanation:

I'm not really sure I understand what you're asking here, but I'll try to make an educated guess.

A solution's **molarity** tells you many **moles of solute** you get **per liter** of solution. You cannot use molarity to find *liters of solute*, so I assume that you're interested in finding the *number of moles* of sodium hydroxide,

So, I think that the question goes like this

How many,moles of solute#"NaOH"# ,you get if the molarity is equal to#"1.0 M"# and the volume of the solution is#"0.05 L"# ?

The interesting thing about molarity is that you can use it as a *conversion factor* to go from *volume* to *moles of solute* and vice versa.

Your solution is said to have a molarity of

#"1.0 M" = "1.0 mol L"^(-1)#

This tells you that **one liter** of this solution contains **mole** of sodium hydroxide, your solute. You can thus use this value to figure out how many moles of solute you'd get in

#0.05 color(red)(cancel(color(black)("L solution"))) * overbrace("1.0 mole NaOH"/(1 color(red)(cancel(color(black)("L solution")))))^(color(purple)("= 1.0 mol L"^(-1))) = color(green)(|bar(ul(color(white)(a/a)"0.05 moles NaOH"color(white)(a/a)|)))#

So, a **moles** of sodium hydroxide.