# Question db008

Apr 19, 2016

4.37 moles. The molar ratio is 1:1, so with unlimited Bromine you would produce the same number of moles of bromine as chlorine.

#### Explanation:

This question really was not stated very well. I am assuming that what was meant was the reaction of chlorine with bromide to form bromine by a redox reaction.

Cl_2 + 2Br^- → 2Cl^- + Br_2

Using Avogadro's number we calculate the number of moles of chlorine as $2.63 x {10}^{24}$ molecules$/ 6.022 x {10}^{23}$ molecules/mole = $0.437 x {10}^{1}$or 4.37 moles.

Chlorine, bromine and iodine
In each case, a halogen higher in the Group can oxidise the ions of one lower down. For example, chlorine can oxidise the bromide ions (in, for example, potassium bromide solution) to bromine:
Cl_2 + 2Br^- → 2Cl^- + Br_2#

http://www.chemguide.co.uk/inorganic/group7/halogensasoas.html Bromine can only oxidise iodide ions to iodine. It isn't a strong enough oxidising agent to convert chloride ions into chlorine.