# Question #a6885

Apr 22, 2016

#### Answer:

$2 \frac{1}{2} g$

#### Explanation:

After the second body is released, both of them are under the same force, hence the distance increases linearly with the relative velocity between them, which is equal to the velocity of the first body after 1sec, i.e. $g$ m/s

This continues for 2 sec.s, so the distance increases by $2 g$ m.

Initially, after the first body is released and before the second one is released, the first body descends a distance of $\frac{1}{2} g$ m.

Hence, the distance is $2 \frac{1}{2} g$ m