Question

Question #f8288

Answer 1

`3.0xx10^4 " miles" " hour"^-2`

Explanation:

Let us use the expression between velocity, time `t` and acceleration `a`, assuming a constant force is applied during the interval.

`v=u+at`
where `v` is final velocity and `u` is initial velocity of car. Substituting given values

`60=0+axx7.2/3600`, seconds to be converted to hours. Solving for `a`
`a=60xx3600/7.2=30000`
`=3.0xx10^4 " miles" " hour"^-2`