How many atoms in #1m^3# of #N_2O# at #"STP"#?

1 Answer
anor277
Apr 28, 2016

How many atoms in #1# #m^3# of #N_2O# at #"STP"#?

Explanation:

In #22.4# #L# at #"STP"#, there are #N_A# gaseous particles, where #N_A = "Avogadro's Number ", 6.022xx10^23*mol^-1#.

So in #1*m^3#, there are #(1000*L)/(22.4*L*mol^-1)# #=# #44.6*mol" *N_2O#

So #"number of atoms"# #=# #44.6*molxxN_Axx3*"atoms"# #=# #" A lot of atoms"#.

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