Question #5785b

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Answer 1 · 2017-06-05T14:57:25

#f!=g.#

Let us first find out all the Images of

#x in D" under "f, i.e, f(x), AA x in D.#

# f(-2)=|-2|+2(-2)=2-4=-2.#

Similarly, #f(-1)=-1, f(0)=0, f(1)=3, f(2)=6.#

Therefore, if we represent #f# as the Set of Ordered Pairs, then,

we have, #f={(-2,-2), (-1,-1), (0,0), (1,3), (2,6)}.#

Similarly, #g={(-2,6), (-1,3), (0,0), (1,-1), (2,-2)}.#

Clearly, #f!=g.#

Enjoy Maths.!