Question #544e6
1 Answer
May 2, 2016
0.954g
Explanation:
Here 200mL0.5M HCl contaims
=0.1gmequivalent HCl
25mLpartly neutralised HCl requires 20.5mL 0.5M NaOH .
forcomlere neutralisation
200mLpartly neutralised HCl requires
164mL0.5M NaOH solution contains
Let the mass of
where equivalent mass of
Here total no.of gm-equivalent of base =total no.of gm-equivalent
of acid