Question

Question #72788

Answer 1

The aqueous tension is `0.1atm`

Explanation:

In order to find the aqueous tension (or vapour pressure) we can first figure out what pressure would the dry gas exert at `10^@C` in a `0.1L` container?

Since the number of mole is constant, we can use the following expression to find the new pressure `P_2`:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)=>P_2=(P_1V_1)/(T_1)xx(T_2)/(V_2)`

`=>P_2=(1atmxx0.080cancel(L))/(273cancel(K))xx(283cancel(K))/(0.1cancel(L))=0.8atm` (1 significant figure since the volume 0.1L is one significant figure).

Therefore, the vapour pressure or aqueous tension would be found by:

`0.90atm-0.8atm=0.1atm`