Question #c3608

So, we need to calculate first the number of moles in the solution from the molecular weight of calcium phosphate, and then divide that by the total liters of the solution to arrive at the require Moles/L ratio that defines molarity. $C a {\left({H}_{2} P {O}_{4}\right)}_{2}$ works out to a molecular weight of 234.05 g/mol, so 660g/234.05g/mol = 2.82 moles.