Question #c3608

1 Answer
Jun 19, 2016



From the definition of a molar solution, we have 1 molar solution = 1 mole of a solute in 1 liter of a solvent.

So, we need to calculate first the number of moles in the solution from the molecular weight of calcium phosphate, and then divide that by the total liters of the solution to arrive at the require Moles/L ratio that defines molarity. # Ca(H_2PO_4)_2# works out to a molecular weight of 234.05 g/mol, so 660g/234.05g/mol = 2.82 moles.

2.82 moles/2.5L = 1.13 moles/L or 1.13 Molar solution.