Question #33e87

1 Answer
May 7, 2016

Answer:

#pH_A# #=# #2.89#

#pH_B# #=# #7.44#

Explanation:

By definition, #pH# #=# #-log_10[H_3O^+]#.

#pH_A# #=# #-log_10[1.3xx10^-3]=2.89#

#pOH_B# #=# #-log_10[4.5xx10^-8]=7.44#

Since #pH+pOH=14#, #pH_B# #=# #6.56#

What does it mean when we say #log_AB=c?#

Can you tell me the values of #log_(10)10# and #log_(10)100?#