# Question 33e87

May 7, 2016

$p {H}_{A}$ $=$ $2.89$

$p {H}_{B}$ $=$ $7.44$

#### Explanation:

By definition, $p H$ $=$ $- {\log}_{10} \left[{H}_{3} {O}^{+}\right]$.

$p {H}_{A}$ $=$ $- {\log}_{10} \left[1.3 \times {10}^{-} 3\right] = 2.89$

$p O {H}_{B}$ $=$ $- {\log}_{10} \left[4.5 \times {10}^{-} 8\right] = 7.44$

Since $p H + p O H = 14$, $p {H}_{B}$ $=$ $6.56$

What does it mean when we say log_AB=c?

Can you tell me the values of ${\log}_{10} 10$ and log_(10)100?#