Question #d893a

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Answer 1 · 2016-12-23T05:43:25

#sf(9.9color(white)(x)ml)#

#sf(H_2SO_4+2NaOHrarrNa_2SO_4+2H_2O)#

#sf(n_(H_2SO_4)=cxxv=0.1xx24.7/1000=2.47xx10^(-3))#

#:.##sf(n_(NaOH)=2.47xx10^(-3)xx2=4.94xx10^(-3))#

#sf(c=n/v)#

#:.##sf(v=n/c)#

#:.##sf(v_(NaOH)=(4.94xx10^(-3))/(0.5)=9.88xx10^(-3)color(white)(x)L)#

#sf(v_(NaOH)=9.9color(white)(x)ml)#