What is the molarity of a #49.0*g# mass of phosphoric acid in a #2.00*L# volume of aqueous solution?

1 Answer
Sep 18, 2016

Answer:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

We get an answer with units #mol*L^-1#.

#"Moles of phosphoric acid "(H_3PO_4)# #=# #(49.0*g)/(97.99*g*mol^-1)# #=# #0.5*mol#.

#"Molarity"# #=# #(0.50*mol)/(2000*cm^3xx10^-3cm^3*L^-1)#

#=# #0.25*mol*L^-1# with respect to #H_3PO_4#.