What molar quantity of the metal salt are present in a #0.667*g# mass of sodium dichromate?

1 Answer
May 11, 2016

Answer:

#"5.10 mmol"#

Explanation:

#"Moles of sodium dichromate" = (0.667*g)/(261.97*g*mol )=2.55xx10^-3 *mol#.

Given the composition of sodium dichromate, #Na_2Cr_2O_7#, there are twice this molar quantity of sodium ions. How many oxygen atoms?