Question

Question #69fd6

Answer 1

`[H_3O^+] = 2.24\times10^-5`

Explanation:

Take the antilog of the negative pH to find the `[H_3O^+]` concentration

antilog`[-4.65] =`

`10^[-4.65] =`

`[H_3O^+] = 2.24\times10^-5`