# Question eebf3

May 15, 2016

$0.179$ $M$

#### Explanation:

The way to find this is given by the formula ${M}_{1} {V}_{1} = {M}_{2} {V}_{2}$ for titrations

Therefore, the sulfuric acid is $0.3$ $M$ and $25$ $m L$ as Volume
i.e. ${M}_{1} = 0.3$ $M$, ${V}_{1} = 25$ $m l$; ${V}_{2} = 42$ $m l$; M_2 =?#

$0.3 \times 25 = 42 \cdot x$
where $x$ is the molarity of sodium hydroxide

$7.5 = 42 x$

$x = 0.17857$ $M$