# How many neutrons in ""^14CH_4?

The number of neutrons in ""^14CH_4 are the same as the number of neutrons in ""^14C.
For $C$, $Z = 6$, therefore there are $8$ neutrons, $8$ fundamental, massive, neutrally charged nuclear particles in the ""^14C nucleus.
How many neutrons in ""^14C{""^2H}_4, $\text{perdeutero"-""^14C-"methane}$?