How do you convert #"255 mm Hg"# to #"atm"#? What about #"620 torr"# to #"PSI"#?

1 Answer
May 18, 2016

THE CONVERSION RATIOS

There is a conversion factor for going from #"mm Hg"# (or #"torr"#) to #"atm"#:

#\mathbf("1 atm" = "760 mm Hg" = "760 torr")#

There also exists a conversion factor for #"PSI"#. I actually don't know it, so I looked it up: https://www.google.com/?gws_rd=ssl#q=psi+to+torr

Turns out it's #\mathbf("51.7149 torr = 1 PSI")#.

(Google is a great resource. You should practice with it!)

PERFORMING THE CONVERSIONS

(1)

Let's start from the equality we just wrote out.

#"1 atm"# #=# #"760 mm Hg"#

What happens if we divide by #"1 atm"#? We get the actual ratio for the conversion.

#(1 cancel"atm")/(1 cancel"atm")# #= 1# #= "760 mm Hg"/"1 atm" = "1 atm"/"760 mm Hg"#

This implies that multiplying by this ratio does NOT change the validity of your answer... only the units. (It preserves your numerical information.)

Thus, we get:

#color(blue)(P_"atm") = 255 cancel"mm Hg" xx "1 atm"/(760 cancel"mm Hg")#

#=# #color(blue)("0.336 atm")#

So now you have the same pressure in different units.

(2)

Like before, we have a ratio that is equal to #1#:

#1 = "51.7149 torr"/"1 PSI" = "1 PSI"/"51.7149 torr"#

This ratio is used as follows:

#color(blue)(P_"torr") = 620 cancel"torr" xx "1 PSI"/(51.7149 cancel"torr")#

#=# #color(blue)("12.0 PSI")#

Again, the same pressure as #"620 torr"#, but in different units.