Question

Question #2ef88

Answer 1

`"315 g"`

Explanation:

All you have to do here is use glucose's molar mass as a conversion factor to determine how many grams would contain that many moles of the compound.

Glucose, `"C"_6"H"_12"O"_6`, has a molar mass of `"180.156 g mol"^(-1)`.

A compound's molar mass tells you the mass of one mole of said compound. In your case, one mole of glucose is said to have a mass of `"180.156 g"`.

So, if one mole of glucose has a mass of `"180.156 g"`, it follows that `1.75` moles will have a mass of

`1.75 color(red)(cancel(color(black)("moles glucose"))) * overbrace("180.156 g"/(1color(red)(cancel(color(black)("mole glucose")))))^(color(purple)("molar mass of glucose")) = "315.3 g"`

Rounded to three sig figs, the answer will be

`"mass of glucose" = color(green)(|bar(ul(color(white)(a/a)"315 g"color(white)(a/a)|)))`