All you have to do here is use glucose's molar mass as a conversion factor to determine how many grams would contain that many moles of the compound.
A compound's molar mass tells you the mass of one mole of said compound. In your case, one mole of glucose is said to have a mass of
So, if one mole of glucose has a mass of
#1.75 color(red)(cancel(color(black)("moles glucose"))) * overbrace("180.156 g"/(1color(red)(cancel(color(black)("mole glucose")))))^(color(purple)("molar mass of glucose")) = "315.3 g"#
Rounded to three sig figs, the answer will be
#"mass of glucose" = color(green)(|bar(ul(color(white)(a/a)"315 g"color(white)(a/a)|)))#