# Question #d4018

##### 1 Answer

we have 2 positive charges Q and q (Q>q) which are not equal, and are separated by distance d.

The electric field due to large charge Q at the mid point of distance of separation d will be given by

The electric field due to small charge q at the mid point of distance of separation d will be given by

**Negative sign indicates opposite direcion of the 2nd field w.r.to first one. k is the coulomb's constant.**

So net field **E** at the mid point of their separation will be just the algebraic sum of their electric fields at a distance d/2.

Hence

And E will have same direction as

If charges were now both negative the net direction will be just opposite.

If they were unlike charges +Q and -q then we are to add the E fields as they have same direction.

The electric field due to small charge -q at the mid point of distance of separation d will be given by

So net E will be

And E will have same direction as