Question

Question #199a9

Answer 1

`60`dB

Explanation:

Given that Sound level of a piano is 50dB.

Total Sound level of `n` similar pianos will be `n times` the level of each piano. We know that `n times` can be written in dB as
`10log_10 n`
In the given problem `n=10`
Therefore `10 times`
`=10log_10 10` dB
`=10xx1` dB
`=10` dB

Total Sound level of `10` similar pianos will be`=50+10=60`dB