Question

Question #cddb4

Answer 1

`1/2`

Explanation:

To do this, factor out the highest degree of `x` from the numerator and denominator.

`lim_(xrarroo)(x-1)/(2x+1)=lim_(xrarroo)(x(1-1/x))/(x(2+1/x))=lim_(xrarroo)(1-1/x)/(2+1/x)`

In evaluating the limit, note that as `x` approaches `oo`, `1/x` will approach `0`.

So, when the limit is evaluated, the constants remain, and the `1/x` goes to `0`:

`lim_(xrarroo)(1-1/x)/(2+1/x)=(1-0)/(2+0)=1/2`