Question #bf75f

1 Answer
Jun 23, 2016

Answering about a center and a radius of this circle.
Center is at point #O(13/2, -1/2)#
Radius is #3/2sqrt(2)#

Explanation:

If the question is about a center and a radius of this circle, we know that the center lies right in the middle of the endpoints of a diameter. Therefore, the coordinates of a center #O(X,Y)# are
#X = (5+8)/2 = 13/2#
#Y = (1+(-2))/2 = -1/2#

The radius #R# is a distance from a center #O(13/2, -1/2)# to any of two endpoints of a diameter. We'll take the point #(5,1)#:
#R = sqrt((13/2-5)^2+(-1/2-1)^2)=3/2sqrt(2)#