Question #eb6dd

1 Answer
Jul 11, 2016

Answer:

#"290 mL isopropyl alcohol"#

Explanation:

Rubbing alcohol is simply a solution of isopropyl alcohol of various concentrations by volume.

The volume by volume percent concentration, #"% v/v"#, tells you how many milliliters of solute, which in this case is isopropyl alcohol, you get per #"100 mL"# of solution.

#color(blue)(|bar(ul(color(white)(a/a)"% v/v" = "mL of solute"/"100 mL of solution" xx 100color(white)(a/a)|)))#

In your case, the solution has a concentration of #"70% v/v"#, which means that you get #"70 mL"# of pure isopropyl alcohol for every #"100 mL"# of solution, i.e. of rubbing alcohol.

You can thus use the volume by volume percent concentration as a conversion factor to calculate how many milliliters of isopropyl alcohol you have in your #"420 mL"# bottle of rubbing alcohol

#420 color(red)(cancel(color(black)("mL rubbing alcohol"))) * overbrace("70 mL isopropyl alcohol"/(100color(red)(cancel(color(black)("mL rubbing alcohol")))))^(color(blue)("= 70% v/v")) = color(green)(|bar(ul(color(white)(a/a)color(black)("290 mL isopropyl alcohol")color(white)(a/a)|)))#

I'll leave the answer rounded two two sig figs.

You can use the same technique to figure out how many milliliters of isopropyl alcohol you have in #"420 mL"# of rubbing alcohol that is #"40% v/v"#.