Question

Question #7ef19

Answer 1

For the given figure

`"In" DeltaBCE and DeltaADE, /_BEC=/_AED->"Vertically opposite"`

Again `(BE)/(DE)=(CE)/(AE)=1/3`

`"So" DeltaBCE and DeltaADE->Similar`

Hence `(BC)/(AD)=(BE)/(DE)=(CE)/(AE)=1/3`

`=>(BC)/(AD)=1/3`

`=>6/(AD)=1/3`

`=>AD=18cm`