# #f(x) = 2x^4-3x^3-5x^2+9x-3# Given that #sqrt(3)# forms two of the roots, find all the roots of the polynomial?

##### 2 Answers

#### Answer:

The roots of the polynonial are:

#### Explanation:

The roots of the polynonial are those values of

Since

The question tells us the

Long dividing

This factorises as:

Hence the two remaining roots are:

Therefore the four roots of

#### Answer:

#### Explanation:

There appears to be error in posting the question.

As mentioned the two zeros are not

I found that the two zeros must be

.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.--.-.-.

Given equation is

Given that two of its zeros are

If we divide the equation (1) by the above quadratic by long division method we get another quadratic which is a factor of equation (1)

To find factors of second quadratic we use split the middle term method

Setting each factor