# Question #d5ddf

Sep 12, 2016

Closed loop is a contour. You can you calculate the flux through a contour ?

I guess you meant, a closed surface which encloses a volume.

In that is the case, the net flux must be zero.

#### Explanation:

From Gauss' law, the next flux through a closed surface is,

${\phi}_{E} = {Q}_{i} / {\epsilon}_{0}$ where, ${Q}_{i}$ is the net enclosed charge and ${\epsilon}_{0}$ is the permittivity of free space (We are assuming that it's vacuum where we are dealing with the problem).

Now, the net charge of a dipole contain charges $q$ and $- q$ is $q + \left(- q\right) = 0$.

Thus, for n dipoles, the net charge is zero as well.

Thus, the net charge enclosed by the surface is zero.

$\implies {Q}_{i} = 0$

Thus, by Gauss' law, ${\phi}_{E} = 0$.