Question

Question #88f84

Answer 1

We need to calculate both sides of the equation, and find a value `c` that satisfies it

Explanation:

We calculate first `f(2)=2*2^2-3*2+1=3`
We then calculate `f(0)=2*0^2-3*0+1=1`

We then calculate `(f(2)-f(0))/(2-0)=(3-1)/(2-0)=1`

We calculate now `f'(x)=4x-3`, and now we need to find a point `c` where `f'(c)=1`, that is `4c-3=1`, but this means `4c=4`, and hence `c=1` is the value we are looking for