Question

Question #ed14d

Answer 1

Given

`B->"Magnetic field"=0.230T" in XZ direction"`

`A->"Area"=pixx(0.065)^2m^2" in XY plane"`

The angle subtended by the magnetic field in the XZ direcion with the direction of area vector i.e normal to the plane of the circular area is `theta=45^@`

So the mag. flux through the area `phi=B*A*costheta`

`=0.23*pi*(0.065)^2*cos45^@Wb`

`=0.002Wb`