# Question #ed14d

Oct 18, 2016

Given

$B \to \text{Magnetic field"=0.230T" in XZ direction}$

$A \to \text{Area"=pixx(0.065)^2m^2" in XY plane}$

The angle subtended by the magnetic field in the XZ direcion with the direction of area vector i.e normal to the plane of the circular area is $\theta = {45}^{\circ}$

So the mag. flux through the area $\phi = B \cdot A \cdot \cos \theta$

$= 0.23 \cdot \pi \cdot {\left(0.065\right)}^{2} \cdot \cos {45}^{\circ} W b$

$= 0.002 W b$