Question

Question #90b80

Answer 1

`x=21`

Explanation:

We have

`(r+x)^2+(14+x)^2=(14+x)^2` Pythagoras. (Tangency)
`x( x + r) = (r + 14) (x + r)` two lectures of the same area.

Here `r` is the right-bottom circumference radius

Solving for `x,r`

`{((14 + r)^2 + (x + r)^2 = (x + 14)^2), (x (x + r) =(r + 14) (x + r)):}`

we obtain

`x=21` and `r = 7`