# Question #82e8d

Aug 5, 2016

$6$ moles of ${\text{CO}}_{2}$ are produced.

#### Explanation:

First, let's consult the formation equation for carbon dioxide from its constituent elements:

${\text{C"_("(s, graphite)") + "O"_2(g) -> "CO}}_{2} \left(g\right)$

As we can see from this equation, the mole ratio of oxygen gas to carbon dioxide gas is $1 : 1$. This means that the number of moles of these two gases will be equivalent when a reaction goes to completion and the moles of the product to 0.

Thus if the ratio is $1 : 1$, the ratio is also $6 : 6$ and the output number of moles of ${\text{CO}}_{2}$ is $6$.