# How many gold atoms in a "carat"?

Aug 9, 2016

$\text{1 carat}$ $=$ $\text{0.007055 oz}$ $=$ $200 \cdot m g$, so...........

#### Explanation:

$\text{No. of moles}$ $=$ $\text{mass"/"molar mass}$ $=$

$\frac{{\text{22 carat"xx200*mg*"carat}}^{-} 1}{196.97 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??mol

And $\text{number of gold atoms}$ $=$

$\frac{{\text{22 carat"xx200xx10^-3g*"carat}}^{-} 1}{196.97 \cdot g \cdot m o {l}^{-} 1} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$, which gives a result as a NOOMBER!