# Question #d943b

Aug 9, 2016

$p H = 10$
In aqueous solution $p H + p O H = 14$; I am not going thru another derivation. It is fairly straighforward.
We are given $\left[{M}^{+}\right] \left[H {O}^{-}\right] = {10}^{-} 8$; in a saturated solution, thus $\left[{M}^{+}\right]$ $=$ $\left[H {O}^{-}\right]$ $=$ ${10}^{-} 4 \cdot m o l \cdot {L}^{-} 1$.
$p O H = 4$, and from above $p H = 10$ as required.