Question #df20b

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Answer 1 · 2016-12-28T11:57:24

Here initial vlocity of the truck is #u =159.2 "km/hr"=(159.2xx10^3)/3600m/s#

Final velocity of the truck #v=0#

The truck retards uniformly during skidding to come to a stop.

The time of skidding #t=5.85s#
So distance of skiding

#s=1/2(u+v)xxt#

#=>s=1/2((159.2xx10^3)/3600+0)xx5.85#

#=>s=129.35m#