Question #bc9cb
1 Answer
Jan 21, 2017
Force becomes four times.
Explanation:
If
#|vecF|=k_{e}\frac {q_{1}q_{2}}{r^{2}}# .....(1)
where#k_e# is Coulomb's constant# = 8.99×10^9 N m^2 C^-2#
Given that both charges are doubled. The new force is
Using equation (1) we have