Is it true that #cos^(-1) x = 1/cos x# ?

2 Answers
Aug 16, 2016

False due to a clash of conventions.

Explanation:

If #n > 1# is a positive integer, then:

#cos^n x = (cos x)^n#

This is a convenience of notation, to avoid having to use parentheses to distinguish, for example:

#(cos x)^2# and #cos (x^2)#

By convention we can write:

#cos^2 x# and #cos x^2#

respectively, without ambiguity.

However, in the case of #-1#, we have a clash of notation. If #f(x)# is a function, then #f^(-1)(x)# is the inverse function. So we denote the inverse of the function #cos x# by #cos^(-1) x#.

graph{y=arccos x [-5.13, 4.87, -1.04, 3.96]}

This is not to be confused with the reciprocal #(cos x)^(-1) = 1/(cos x)#.

graph{1/cos x [-10.3, 9.7, -4.9, 5.1]}

Since there is no other convenient notation for the inverse function (apart from the ungainly name #arccos#), we give it priority when it comes to the expression #cos^(-1) x#.

Sorry.

Aug 17, 2016

Depends if you consider it as an equation or as an identity.

Explanation:

This affirmation has sense only as an equation.
Iteratively you can find a solution such as

#arccos(0.446048) = 1/cos(0.446048)#

Attached a plot showing #arccos(x)# in blue and #1/cos(x)# in red.

enter image source here