Question #ab197

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Answer 1 · 2016-08-17T10:00:52

See the Explanation given below.

#x=log (1/9)/ log y# : Upto this, it is OK. Now, we proceed further as

shown below :

#:. logy=log(1/9)/x=1/xlog(1/9)=log(1/9)^(1/x)#.

Since, #log# function is #1-1#, we have,

#y=(1/9)^(1/x)#.

Otherwise, we can proceed further from this step# : y^x=1/9#

#:. (y^x)^(1/x)=(1/9)^(1/x)#

#:. y^(x*1/x)=(1/9)^(1/x)#, i.e.,

# y =(1/9)^(1/x)#, as we have derived before!

Enjoy Maths.!