# Question #63d55

Aug 18, 2016

$\sqrt{77} \text{ lies between } 8 \mathmr{and} 9$

#### Explanation:

Let's look at the perfect squares which are close to 77.

$64 = {8}^{2} \mathmr{and} 81 = {9}^{2}$

$\sqrt{64} < \sqrt{77} < \sqrt{81}$

$8 < \sqrt{77} < 9$