Question

`a_n = sin(pi n/6)+cos(pi n)` ?

Answer 1

See below.

Explanation:

`a_n = sin(pi n/6)+cos(pi n)`

This is a periodic sequence in which

`a_n = a_(n+12)` with minimum and maximum values such that

`-2 le a_n le 1+sqrt(3)/2`

Attached a sequence plot