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Question #6b2a6

1 Answer

Aug 23, 2016

#sqrt(2y-3y^2) +C#

Explanation:

#d/(dy)sqrt(2y-3y^2) = 1/2(2-6y)/sqrt(2y-3y^2) =(1-3y)/sqrt(2y-3y^2) #

so

#int (1-3y)/(sqrt(2y-3y^2))dy = sqrt(2y-3y^2) +C#

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