What is #log_81 3# ?
1 Answer
Aug 28, 2016
Explanation:
The change of base formula tells us that for
#log_a b = log_c b / log_c a#
Hence we find:
#log_81 3 = log_3 3 / log_3 81 = log_3 3 / log_3 3^4 = 1/4#